Question

sec(a+b)=2=cosec(a-b), find a and b​

Answer 1

Answer:

a+b=2

ab=2 this is the correct answer

Answer 2

Answer:

The value of ∠A = 22.5°

The value of ∠B = 22.5°

Step-by-step explanation:

We have,

$\sec(A+B)=\sqrt{2} and \csc(A-B)=\infty$

To find, the value of ∠B = ?

$\sec(A+B)=\sqrt{2}$

⇒ $\sec(A+B)=\sec 45 [ ∵ \sec 45=\sqrt{2}$

⇒ A + B = 45° --(1)

Also,

$\csc(A-B)=\infty$

⇒ $\csc (A-B)=\csc 90$

⇒ A - B = 90° ---(2)

Subtracting (1) from (2), we get

A + B - ( A - B) = 45° - 90

⇒  A + B - A + B = - 45°

⇒2B =  45°

⇒ B =  22.5°

Hence, the value of ∠B = - 22.5°

Therefore value of  ∠A = ∠B = 22.5°