Question

sec A /cosec A=??
plz answer correctly
other wise I will report you​

Answer 1

♣ Qᴜᴇꜱᴛɪᴏɴ :

Value of :-

$\large\boxed{\sf{\dfrac{sec\:A}{cosec\:A}}}$

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♣ ᴀɴꜱᴡᴇʀ :

$\large\boxed{\sf{\dfrac{sec\:A}{cosec\:A}=tan\:A}}$

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♣ ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴꜱ :

We know :

$\boxed{\sf{sec\:A=\dfrac{Hypotenuse}{Base}}}$

$\boxed{\sf{cosec\:A=\dfrac{Hypotenuse}{Height}}}$

$\sf{\dfrac{sec\:A}{cosec\:A}=\left(\displaystyle \dfrac{\dfrac{Hypotenuse}{Base}}{\dfrac{Hypotenuse}{Height}}\right)}$

$\sf{\dfrac{sec\:A}{cosec\:A}=\left(\displaystyle \dfrac{Hypotenuse\times Height}{Base\times Hypotenuse}\right)}$

$\sf{\dfrac{sec\:A}{cosec\:A}=\left(\displaystyle \dfrac{\cancel{Hypotenuse}\times Height}{Base\times \cancel{Hypotenuse}}\right)}$

$\sf{\dfrac{sec\:A}{cosec\:A}=\left(\displaystyle \dfrac{Height}{Base}\right)}$

Also :

$\boxed{\sf{tan\:A=\dfrac{Height}{Base}}}$

Hence :

$\large\boxed{\sf{\dfrac{sec\:A}{cosec\:A}=tan\:A}}$