Question

sec A . cot B - sec A - 2 cot B + 2 = 0 find A and B

Answer 1

Solution :

secAcotB - secA - 2cotB + 2 = 0

=> secA( cotB - 1 ) - 2( cotB - 1 ) = 0

=> ( cotB - 1 )( secA - 2 ) = 0

=> cotB - 1 = 0 or secA - 2 = 0

=> cotB = 1 or secA = 2

=> cotB = cot45° or secA = sec 60°

Therefore ,

B = 45° or A = 60°

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