Question

(Sec A + tan A -1) (sec A - tan A +1) = 2 tanA

Answer 1

Answer:

Step-by-step explanation:

(secA+tanA-1)(secA-tanA+1)=2tanA

sec2A-[tanA-1)^2 =2tanA

1/cos2A-(tan2A-2tanA+1)=2tanA

1+tan2A-tan2A+2tanA-1=2tanA

(1-1)+(tan2A-tan2A)+2tanA=2tanA

0+0+2tanA=2tanA

2tanA=2tanA

hence proved