Question

(sec a + tan a ) (1 -sin a)​

Answer 1

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Answer 2

Answer:

(sec a + tan a ) (1 -sin a)​

$=seca-seca(sina)+tana-tana(sina)\\=sec a - \frac{1}{cos a} (sin a) + tan a - tan a (sin a)\\=seca - tana+tana-tana(sina)\\=seca- tana(sina)\\=seca- \frac{sina}{cos a} (sina)\\= \frac{1}{cos a}- \frac{sin^2a}{cos a}\\=\frac{1-sin^2a}{cosa}\\=\frac{cos^2a}{cosa}\\=cosa$