Question

(sec A+ tan A) (1-sin A)=?​

Answer 1

hey friend

it's your ans-

Que :-

$(sec A+ tan A) (1-sin A)=?$

Ans :-

$cosA$

Solution :-

$= (sec A+ tan A) (1-sin A)$

$= (\frac{1}{cos A} + \frac{sinA}{cosA }) \: (1-sin A)$

$= \frac{(1 + sinA}{cosA} (1-sin A)$

$= \frac{ ( 1+ sinA ) (1-sin A)}{cosA}$

$= \frac{1 - {sin}^{2}A}{cosA}$

$= \frac{ {cos}^{2}A}{ cosA }$

$= cosA$

Therefore, (sec A+ tan A) (1-sin A) = cosA

hope helpful..

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