Question

(sec A+ tan A) (1-sinA)​

Answer 1

Explanation:

[(secA+tanA)(1−sinA)]

⇒[(

cosA

1+sinA

)(1−sinA)]

⇒

cosA

1−sin

2

A

=

cosA

cos

2

A

⇒cosA

Hence, the answer is cosA.

Answer 2

Answer:

cos A

Explanation:

(sec A + tan A) ( 1-sinA)

= ( 1÷ cos A + sin A ÷ cos A) ( 1-sin A).....

[ secA=1÷cosA]

[ tanA= sinA÷cosA]

= ( 1+sin A÷ cos A) (1-sinA)

= (1^2 - sin^2 A ÷ cos A ) ...[(1+sinA)(1-sinA)

= 1^2 - sin^2 A

= 1 - sin^2 A ÷ cos A

= cos^2 A ÷ cos A....[ sin^2A + cos^2 A= 1]

= [1-sin^2A = cos^2 A]

= cos A

the solution is getting jumbled up as i send it .....please tell if you cannot understand....