Question

[Sec A+ tan A] [1-sinA] = ??​

Answer 1

Answer:

cos A

Step-by-step explanation:

hope you understand

bye

Answer 2

Step-by-step explanation:

[Sec A + Tan A] [1- Sin A]

{Sec A = 1/Cos A} {Tan A = SinA/ CosA}

=> [1/Cos A + Sin A/Cos A] [1-Sin A]

=> [1+ Sin A/Cos A] [1-Sin A]

using identity,

=> (a+b)(a-b) = a²-b²

=> 1-Sin² A/Cos A

{Cos²A = 1-Sin² A}

=> Cos²A/CosA

=> Cos A

hope it helps....