(sec A - tan A)² =1-sin A/1+sin A
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LHS=(secA-tanA)²
=[(1-sinA)/cosA]²
=(1-sinA)²/cos²A
=(1-sinA)²/(1-sin²A)
=(1-sinA)(1-sinA)/(1+sinA)(1-sinA)
=(1-sinA)/(1+sinA)
=RHS
HENCE PROVED
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