( sec A – tan A) ²= (1 -sin A ) / ( 1 + sin A )
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Answer:
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Answered by
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Answer:
LHS = RHS
Step-by-step explanation:
LHS = ( sec A - tan A ) ^ 2
= ( 1 / cos A - sin A / cos A ) ^ 2
= [ ( 1 - sin A ) / cos A ] ^ 2
= [ ( 1 - sin A ) ^ 2 / cos ^ 2 A ]
= [ ( 1 - sin A ) ^ 2 / 1 - sin ^ 2 A ]
= [ ( 1 - sin A ) ^ 2 / ( 1 - sin A ) ( 1 + sin A ) ]
= [ ( 1 - sin A ) / ( 1 + sin A ) ]
= RHS
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