Question

Sec A + tan A = 2/3
Find sin A

Answer 1

Answer:

5/13

Step-by-step explanation:

we know,

sec²A-tan²A=1

(secA-tanA)(secA+tanA)=1

putting secA + tanA = 2/3 (given)

so, (secA-tanA) × 2/3=1

(secA-tanA)= 3/2...........(ii)

secA + tanA= 2/3...........(i)

adding (i) and (ii),we get,

2secA=13/12=hypotenuse/base

altitude² =hyp²- base

=13²-12²

= 25

so, alt=√25=5

sinA = alt/hyp=5/13

Since, sinA= 5/13