Question

sec a-tan a÷cosec a+cot a=cosec a+cot a÷seca-tana​

Answer 1

Answer:

= (sec a + tan a)/(cosec a + cot a) (1+sin a)sin a/ cos a (1 + cos a) = ( (1-сos a)/sin a) / ( (1-sin a)/cos a) (cosec a - cot a)/(sec a - tan a)

Answer 2

sec attan a/cosec a tcot a=cosec a -cot

a/sec a-tan a prove it

devanshs370 Helping Hand

Answe

32 2.0

= (sec a + tan a)/(cosec a + Cot a)

(1+sin a)sin al cos a (1 +cos a)

( (1-cos al/sin a) /(1-sin a)/cos a)

= (coseca - cot a)/(sec a tan a)

hence proved