Question

(sec A – tan A) (sec A + tan A) – (cosec A – cot A) (cosec A + cot A) बराबर है -
(i) 2 (ii) 1 (iii) 0 (iv) 1/2

Answer 1

Answer:

(sec A – tan A) (sec A + tan A) – (cosec A – cot A) (cosec A + cot A) बराबर है -

(i) 2 (ii) 1✔ (iii) 0 (iv) 1/2

Answer 2

Question :------- (sec A – tan A) (sec A + tan A) – (cosec A – cot A) (cosec A + cot A) = ?

Formula to be used :------

• (sec²A - tan²A) = 1
• (cosec²A - cot²A ) = 1
• (a-b)(a+b) = 1

Using all we get,

(sec A – tan A) (sec A + tan A) – (cosec A – cot A) (cosec A + cot A)

→ (sec²A-tan²A)(cosec²A-cot²A)

→ 1×1

→ 1 (Option B)

$\color {red}\large\bold\star\underline\mathcal{Extra\:Brainly\:Knowledge:-}$

$\mathcal{Trignometric\:\:Identities}$ :--------

→ sin²θ = 1 − cos²θ

→ cos²θ = 1 − sin²θ

→ tan²θ + 1 = sec²θ

→ tan²θ = sec²θ − 1

→ cot²θ + 1 = csc²θ

→ cot²θ = csc²θ − 1

$\mathcal{BE\:\:BRAINLY}$