Question

sin⁴ A – cos⁴ A बराबर है
(i) 1 (ii) sin²A – cos²A (iii) 0 (iv) tan²A

Answer 1

Question :---- we have to Find value of sin⁴ A – cos⁴ A ?

Formula used :---

• sin²a + cos²a = 1
• (a⁴-b⁴) = (a²-b²)(a²+b²)

sin⁴ A – cos⁴ A

→ (sin²A - cos²A)(sin²A+cos²A)

→ (sin²A-cos²A) (B) (Ans)

$\color {red}\large\bold\star\underline\mathcal{Extra\:Brainly\:Knowledge:-}$

$\textsf{Trignometric\:Identity\:}[tex]</p><p></p><p>→ sin²θ = 1 − cos²θ</p><p>→ cos²θ = 1 − sin²θ</p><p>→ tan²θ + 1 = sec²θ</p><p>→ tan²θ = sec²θ − 1</p><p>→ cot²θ + 1 = csc²θ</p><p>→ cot²θ = csc²θ − 1</p><p></p><p></p><p></p><p>[tex]\mathcal{BE\:\:BRAINLY}$

Answer 2

$\huge\mathfrak\purple{Answer}$

$options (!!) {sin}^{2}A - {cos}^{2}A$

$\huge\mathfrak\blue{Solution}$

${sin}^{4}A - {cos}^{4}A\\ \\ {a}^{4} - {b}^{4} = ({a}^{2} - {b}^{2}) ({a}^{2} + {b}^{2} ) \\ \\ ({sin}^{2}A - {cos}^{2}A) ({sin}^{2}A + {cos}^{2}A ) \\ \\ ({sin}^{2}A + {cos}^{2}A = 1 ) \\ \\ ({sin}^{2}A - {cos}^{2}A ) × 1 \\ \\ {sin}^{2}A - {cos}^{2}A$