Math, asked by Ggyhhjjnvfgbnh3402, 9 months ago

sin² A – sec² A + cos² A + tan² A बराबर है,
(i) 0 (ii) 1 (iii) sin² A (iv) cos² A

Answers

Answered by Anonymous
2

Answer:

0

Step-by-step explanation:

sin² A – sec² A + cos² A + tan² A

sin^2A + cos^2A + tan^2A - sec^2A

1 - 1

0

Answered by MrBhukkad
0

Answer:

HEY MATE,

HERE'S YOUR ANSWER.

=> Option (i) 0

Explanation:

Sin²A - Sec²A + Cos²A + Tan²A

= Sin²A + Cos²A - Sec²A + Tan²A

= Sin²A + Cos²A - (Sec²A - Tan²A)

= 1 - 1

= 0

HOPE IT HELPS YOU.

PLZ.., MARK ME BRAINLIEST.

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