Question

∫sec (ax+b) tan(ax+b)dx=​

Answer 1

Answer:

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Answer 2

Answer:

the answer is  = sec(ax+b)/a + C

Step-by-step explanation:

∫sec(ax+b)tan(ax+b)dx

define u = ax+b

now differentiating u wrt to x we get du/dx = a

or 1/a dx = du

Now it implies :

= 1/a∫sec u.tan u du [by formula]

= 1/a sec u

now substitute the value of u as ax+b we get :

sec(ax+b)/a + C

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