Math, asked by dssinghindia, 9 months ago

(sec Θ + cosec Θ)(sin Θ+cos Θ) = 2+ sec Θ . cosec Θ

Answers

Answered by streetburner
1

Step-by-step explanation:

(sin Θ+cos Θ)^2 =(2+ sec Θ*cosec Θ)sin Θ*cos Θ

(sin Θ+cos Θ)^2 = 2sin Θ*cos Θ+1

LHS = (sin Θ)^2 + (cos Θ)^2 + 2sin Θ*cos Θ

= 1 +Sin2Θ

RHS = Sin2Θ +1

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