Question

sec square 54 - cot square 36 square 57 - 10 square 33 + 2 sin square 38 square 52 minus sin square 45 (without using trigo tabel evaluate​

Answer 1

Answer:

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cot 36 = tan(90-36) = tan 54

we know sec² 54 - tan² 54 = 1

tan 33 = cot (90-33) = cot 57

cosec² 57 - cot² 57 = 1

sec² 52 = cosec² (90-52) = cosec² 38

sin 38 * cosec 38 = 1

sin² 45 = 1/2

substituting these in the given  expression:  

 [ 1 ] / [1 + 2 * 1 - 1/2 ]

 

= 2/5

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