sec square theta - tan square theta equal to 1
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Answer:
TO PROVE: 1 + Tan²θ = Sec²θ
Tan θ = (Sin θ) / (Cos θ)
∴ Tan²θ = (Sin θ / Cos θ)² ..... (1)
L.H.S = 1 + Tan²θ
(substituting from equation 1 we get)
L.H.S. = 1 + (sin θ/cos θ)²
∴ L.H.S = 1 + (Sin²θ / Cos²θ)
∴ L.H.S. = (Cos²θ + Sin²θ) / Cos²θ
But, we know that - Cos²θ + Sin²θ = 1
∴ L.H.S. = 1 / Cos²θ
∵ 1 / Cosθ = Secθ
∴ L.H.S. = Sec²θ = R.H.S.
as LHS = RHS... hence prooved
1 + Tan²θ = Sec²θ
Step-by-step explanation:
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Answered by
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Answer:
Step-by-step explanation:
do it by writing its ratios.
sec=hyp/adj
tan=opp/adj
hope you could do it.
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