sec+tan=4 find sin=?
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1
sec∅+tan∅=4
sec∅-tan∅=1/4
so 2sec∅=4+1/4=17/4
sec∅=17/8
cos∅=8/17
sin∅=15/17
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4
Sec+tan=4
As we know.
Sec2=1+tan2
Sec2-tan2=1
(a2+b2) =(a+b) (a-b)
.
So
(Sec + tan)(Sec - tan) =1
Given sec +tan=4
Sec-tan=1/4........ Eq 1
Now compare and plot on a right angle triangle so u get ur answer..
You get sin 15/17
As we know.
Sec2=1+tan2
Sec2-tan2=1
(a2+b2) =(a+b) (a-b)
.
So
(Sec + tan)(Sec - tan) =1
Given sec +tan=4
Sec-tan=1/4........ Eq 1
Now compare and plot on a right angle triangle so u get ur answer..
You get sin 15/17
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