sec θ - tan θ / sec θ + tan θ
1. sec θ + sin θ
2. cosec θ + sin θ
3. 1 - 2 sec θ tan θ + 2 tan² θ
4. cot θ + tan θ - 1
Answers
Answered by
3
Answer:
1.0
2.0
3.0
4.0
Step-by-step explanation:
hope that's helpful for you
Answered by
3
Step-by-step explanation:
here I'm assuming theta as 'a'
sec a - tan a / sec a + tan a
sec a = 1/cos a
tan a = sin a/cos a
(1/cos a - sina /cos a )/ 1/cos a + sin a/cos a
1-sin a / cos a / 1+ sina /cos a
1-sin a / 1+ sina
1-sin a x 1- sin a / 1+ sina × 1- sin a
1 + sin^2 -2sin / 1 - sin^2
1- sin^2 = cos^2
1 + sin^2 -2sin/ cos^2
dividing by cos^2
1/cos^2a+ sin^2a/cos^2a -2sina/cos^2a
sec^2a + tan^2a-2(tan a. seca)
sec^2 = 1 + tan^2 a
1 + tan^2 a + tan^2a-2(tan a. seca)
1 + 2tan^2 -2(tan a. seca)
3. 1 - 2 sec θ tan θ + 2 tan² θ
is correct one
mark me brainlist plzzzzx
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