Math, asked by vinodkumarregar587, 11 months ago

sec θ - tan θ / sec θ + tan θ
1. sec θ + sin θ
2. cosec θ + sin θ
3. 1 - 2 sec θ tan θ + 2 tan² θ
4. cot θ + tan θ - 1​

Answers

Answered by avverma6
3

Answer:

1.0

2.0

3.0

4.0

Step-by-step explanation:

hope that's helpful for you

Answered by adityayadav06050
3

Step-by-step explanation:

here I'm assuming theta as 'a'

sec a - tan a / sec a + tan a

sec a = 1/cos a

tan a = sin a/cos a

(1/cos a - sina /cos a )/ 1/cos a + sin a/cos a

1-sin a / cos a / 1+ sina /cos a

1-sin a / 1+ sina

1-sin a x 1- sin a / 1+ sina × 1- sin a

1 + sin^2 -2sin / 1 - sin^2

1- sin^2 = cos^2

1 + sin^2 -2sin/ cos^2

dividing by cos^2

1/cos^2a+ sin^2a/cos^2a -2sina/cos^2a

sec^2a + tan^2a-2(tan a. seca)

sec^2 = 1 + tan^2 a

1 + tan^2 a + tan^2a-2(tan a. seca)

1 + 2tan^2 -2(tan a. seca)

3. 1 - 2 sec θ tan θ + 2 tan² θ

is correct one

mark me brainlist plzzzzx

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