Math, asked by vijayasms1, 1 year ago

Sec theta -1/sec theta +1=sin^2 theta/(1+cos theta)^2​

Answers

Answered by Itzraisingstar
2

Answer:

Step-by-step explanation:

(sin theta + 1 + cos theta) × (sin theta - 1 + cos theta) × sec theta cosec theta

[(sin theta + cos theta)²-1] × 1/cos theta sin theta

(sin (theta)² + 2sin theta cos theta + cos (theta)²-1) × 1/cos theta sin theta

(1+2sin theta cos theta -1) × 1/cos theta sin theta

sin 2 theta × 1/cos theta sin theta

2 sin theta cos theta × 1/cos theta sin theta

by reducing the expression

2

Answered by Sudhir1188
3

Step-by-step explanation:

PLEASE FIND THIS ATTACHMENT.

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