sec theta-1/tan theta=tan theta/sec theta +1
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1
Answer:
1/cos-cos/sin=sin+1
sin-cos square/cos×sin=sin+1
sin-1+sin square/cos×sin=sin+1
sin square/cos×sin=2
sin/cos=2
tan=2
anshupatel7:
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Answered by
1
Answer:
we know that
sec^2 theta -tan^2 theta =1
sec^2 theta -1= tan^2 theta
(sec theta +1)(sec theta-1)=(tan theta)(tan theta)
sec theta -1/tan theta = tan theta/ sec theta+1
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