Math, asked by jamijamshid95, 9 months ago

(sec theta -cos theta)(cot theta +tan theta) =?​

Answers

Answered by sumbalshahz1710
1

Answer:

Step-by-step explanation: (secQ-cosQ) (cotQ+tanQ)

=(1/cosQ - cosQ) (cosQ/sinQ+sinQ/cosQ)

=(1-cos^2Q)/cosQ(cos^2Q+sin^2Q)/sinQcosQ

=(sin^2Q/cosQ)(1/sinQcosQ)

=sinQ/cosQcosQ

=tanQsecQ

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