sec theta minus tan theta equals to 1 by root 3 then find the value of sec theta and tan theta
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sec x-tanx=1/√3
1-sinx=cosx/√3
sq. both sides
1+sin^2x-2sinx=cos^2x/3
3+3sin^2x-(1-sin^2x)-6sinx=0
2sin^2 X -6sinx+2=0
let sin x=t
2t.^2-6t+2=0
solve u will get t I. e., sinx,, from there u can calculate other values also
1-sinx=cosx/√3
sq. both sides
1+sin^2x-2sinx=cos^2x/3
3+3sin^2x-(1-sin^2x)-6sinx=0
2sin^2 X -6sinx+2=0
let sin x=t
2t.^2-6t+2=0
solve u will get t I. e., sinx,, from there u can calculate other values also
sosboto:
But i need the value of sec theta
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