sec theta - sec ^2 theta + tan ^2 theta / sec theta + sec ^2 theta - tan ^2 theta = 1- cos theta /1+ cos theta
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As you can see in the picture I've used one trigonometric identity and one algebraic identity to solve the question.
The identity can be written in the form of (a-b)(a+b)=a^2 - b^2
Putting the given value of 2 in the equation we get a linear equations, which we add to the second equation.
It directly gives us the value of tan(theta)
I won't suggest using the inverse methods because tan(theta) can approach to many different values.
If you need help on any question feel free to ask me.
The identity can be written in the form of (a-b)(a+b)=a^2 - b^2
Putting the given value of 2 in the equation we get a linear equations, which we add to the second equation.
It directly gives us the value of tan(theta)
I won't suggest using the inverse methods because tan(theta) can approach to many different values.
If you need help on any question feel free to ask me.
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