sec theta/sec theta+1sec theta/sec theta-1=2 cosec^theta
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Hi,
Here I am using A instead of theta.
LHS = secA/(secA+1) + secA/(secA-1)
= SecA[ 1/(secA+1) + 1/(secA-1 ) ]
= SecA[ ( secA-1+secA+1 )/(sec² A-1²) ]
= SecA[ 2secA/tan² A ]
= 2sec²A/ tan² A
= ( 2/cos² A ) / ( sin² A/cos² A )
= 2/sin² A
= 2cosec²A
= RHS
I hope this helps you.
:)
Here I am using A instead of theta.
LHS = secA/(secA+1) + secA/(secA-1)
= SecA[ 1/(secA+1) + 1/(secA-1 ) ]
= SecA[ ( secA-1+secA+1 )/(sec² A-1²) ]
= SecA[ 2secA/tan² A ]
= 2sec²A/ tan² A
= ( 2/cos² A ) / ( sin² A/cos² A )
= 2/sin² A
= 2cosec²A
= RHS
I hope this helps you.
:)
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