(sec thetha+1)(sec thetha-1)=?
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Answered by
1
Answer:
(sec thetha +1)(sec thetha -1) is sec^2 thetha -1^2
tht is tan^2 thetha I wish u understood
Answered by
1
Answer:
(secθ + 1)(secθ - 1)
= (sec²θ - 1²) [(a+b)(a-b) = a²-b² ]
= sec²θ - 1
= tan²θ. [ sec²θ - 1 = tan²θ ]
hope it may help you
have a nice day
Answered by
0
Answer:
(secθ + 1)(secθ - 1)
= (sec²θ - 1²) [(a+b)(a-b) = a²-b² ]
= sec²θ - 1
= tan²θ. [ sec²θ - 1 = tan²θ ]
hope it may help you
have a nice day
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