Sec x =-5/4 , x lies in 2nd quadrant.then what will be value of sin x/2 ?
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In second quadrant sin is positive.
By Pythagorean’s theorem,
Sin x= 3/5
Cos x= -4/5
Sin x/2 = root(1-cos x)/2
= root (1+4/5)/2
= root (9/5)/2
= 3/2 root5
Hope it helps...
Please mark my answer as the brainliest...
By Pythagorean’s theorem,
Sin x= 3/5
Cos x= -4/5
Sin x/2 = root(1-cos x)/2
= root (1+4/5)/2
= root (9/5)/2
= 3/2 root5
Hope it helps...
Please mark my answer as the brainliest...
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