Question

Sec x - cos x = tan x sin x

Answer 1

Answer:

The given question is solved in the uploaded photo

Answer 2

Answer:

L.H.S.:

$= > \sec(x) - \cos(x) \\ = > \frac{1}{ \cos(x) } - \cos(x) \\ = > \frac{1 - {cos}^{2}(x) }{ \cos(x) } \\ = > \frac{ {sin}^{2} (x)}{ \cos(x) } \\ = > \frac{ \sin(x) }{ \cos(x) } . \sin(x) \\ = > \tan(x) . \sin(x) \\ = > \tan(x) \sin(x) = r.h.s. \\ \\ hence \: \: \: \: proved$

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