Sec x - cosec x =4 then find the value of sinx - cosx= ?
Answers
Step-by-step explanation:
hey mate
if started the basics of trignometry it will be helpful
so here is your answer
__________________________________________
If sin x + cosec x = 4, then what is sin^10 x + cosec^10 x?
sin x + cosec x = 4, or
sin x + 1/sin x = 4, or
sin^2 x + 1 = 4 sin x, or
sin^2 x - 4 sin x+ 1 = 0. Let sin x = m, Then
m^2–4m+1 = 0
m1 = [4+(16–4)^0.5]/2
= [2+√3], or
m2 = [2-√3]
sin^10 x + cosec^10 x = [2+√3]^10 + 1/[2+√3]^10
= [2+√3]^10 + [2-√3]^10/[2+√3]^10*[2-√3]^10
= [2+√3]^10 + [2-√3]^10
= 524174 + 1.9^(-6)
= 524174
OR
sin^10 x + cosec^10 x = [2-√3]^10 + 1/[2-√3]^10
= [2-√3]^10 + [2+√3]^10/[2-√3]^10*[2+√3]^10
= [2-√3]^10 + [2+√3]^10
= 524174 + 1.9^(-6)
= 524174
sin^10 x + cosec^10 x = 524174
hope it helps
plz mark this answer as the brainliest
:):)