Question

sec°+tan°=5 than the value of sec°-tan° pls answer this question i will mark brainliest​

Answer 1

Answer:

0.2

Step-by-step explanation:

you know that

$sec^2 x - tan^2 x = 1$

so by

$a^2 - b^2 = (a - b)(a + b)$

$sec^2 x - tan^2 x = (sec x - tan x) (sec x + tan x) = 1$

if

$sec x + tan x = 5$

then

$(sec x - tan x) = \frac{1}{(sec x - tan x)} = \frac{1}{5} = 0.2$