Math, asked by upendraguddili, 11 months ago

Sec16.cosec74-cot74.tan16

Answers

Answered by XxxXXJAYXXxxX

0

Answer:

SEC 16 SEC 16 - COT 74 COT 74

SEC²16 - TAN²16

SEC²16 - TAN² 16

1

BECOS SEC²∅-TAN²∅=1

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Answered by punit2508

0

Answer:

Step-by-step explanation:

cosec(90-x) = sec x

tan(90-x) = cot x

sec²x = 1+tan²x

Sec16.cosec74-cot74.tan16

=sec16(cosec[90-16]) - (tan[90-16])tan16

=sec²16 - tan²16

=1

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