Math, asked by neha2445, 1 year ago

sec17/cosec73+tan68/cot22+cos2 44 +cos2 46

Answers

Answered by anmoldwivedi123
38
check the photo.......!!!
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Answered by mysticd
3

/* There is a mistake in the last term .

It may be like this */

 \red{ Value \:of \: \frac{sec 17\degree}{Cosec 73 \degree } + \frac{tan 68\degree}{Cot 22 \degree } + \frac{cos^{2} 44\degree}{Sin^{2}46 \degree } }

 = \frac{sec (90- 73\degree)}{Cosec 73 \degree } + \frac{tan (90-22\degree)}{Cot 22 \degree } + \frac{cos^{2} (90-46\degree)}{sin^{2}46 \degree }

 = \frac{cosec 73\degree}{Cosec 73 \degree } + \frac{cot 22\degree}{Cot 22 \degree } + \frac{sin^{2} 46\degree}{sin^{2}46 \degree }

 = 1 + 1 + 1 \\= 3

Therefore.,

 \red{ Value \:of \: \frac{sec 17\degree}{Cosec 73 \degree } + \frac{tan 68\degree}{Cot 22 \degree } + \frac{cos^{2} 44\degree}{Sin^{2}46 \degree } }\green {= 3}

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