Question

(sec2 37 - cot2 53) tan21 tan69 - sin 51 cos 39 - cos 51 SIN 39

Answer 1

Required answer is in the attachment.

Answer 2

Answer:

Step-by-step explanation:

Sec 37°×cosec 53°- tan 37°×cot 53°

Sec(90°-53°) ×cosec 53°- tan(90°-53°) ×cot 53°

Cosec 53°×cosec 53°- cot 53°×cot 53°

Cosec^2 53°- cot^2 53°

Sin^37°- cot^53°

(1+tan^2 37°- cot^53°)

(1+cot^53°- cot^53°)

1+0

1