Question

Sec² theta - 1÷ tan²theta = 1

Answer 1

Answer:

$\frac{ { \sec}^{2} \alpha - 1}{ { \tan}^{2} \alpha } = 1 \\ \\ ({ \sec }^{2} \alpha - 1 = { \tan }^{2} \alpha ) \\ \\ threfore \\ \frac{ { \tan }^{2} \alpha }{ { \tan }^{2} \alpha } = 1$

Answer 2

Step-by-step explanation:

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