(sec²A-1)cot²A=1
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Answered by
2
lhs=
sec^2A-1=Tan^2A
Our qn becomes:
Tan^2A.Cot^2A=tan^2A/tan^2A=1=Rhs.
sec^2A-1=Tan^2A
Our qn becomes:
Tan^2A.Cot^2A=tan^2A/tan^2A=1=Rhs.
Answered by
4
hey friend, nice question
we known That tan and cot are reverse of each other so tan into cot Will be one
so here is the answer
by trigonometric identities
tansquare is sec square minus 1
so by putting values we get tan square into cot square that is one
hope this will help u and don't need to say thanks just answer my latest question as a remark of thanks .
we known That tan and cot are reverse of each other so tan into cot Will be one
so here is the answer
by trigonometric identities
tansquare is sec square minus 1
so by putting values we get tan square into cot square that is one
hope this will help u and don't need to say thanks just answer my latest question as a remark of thanks .
lugvv:
hey
answe mine
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