sec²theta - cos²theta = sin2 theta (sec2 theta +1 )
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Given :-
sec²∅ - cos²∅ = sin²∅ (sec²∅ + 1)
Solution :-
R.H.S.
⇒ sin²∅ (sec²∅ + 1)
⇒ 1 - cos²∅ ( sec²∅ + 1)
⇒ sec²∅ - cos²∅sec²∅ + 1 - cos²∅ ( cos²∅ = 1/sec²∅)
⇒ sec²∅ - 1 + 1 - cos²∅
⇒ sec²∅ - cos²∅ = L.H.S.
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Answer:
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