(sec300°+tan300°)(sec300°-tan300°)
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Answered by
1
(A+B)(A-B) = A²-B²
(sec300°+tan300°)(sec300°-tan300°)=sec²300°-tan²300°
sec²A-tan²A=1
sec²300°-tan²300°=1
(sec300°+tan300°)(sec300°-tan300°)=sec²300°-tan²300°
sec²A-tan²A=1
sec²300°-tan²300°=1
HardikMittal:
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Answered by
0
(sec300+tan300)(sec300-tan300)=sec^{2} 300-tan^{2} 300
=1
=1
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