Question

sec3a/sec2a-1 + cosec3a/cosec2-1=seca coseca (seca+ coseca)

Answer 1

Answer:

L.H.S.

(1+cotA+tanA)(sinA−cosA)

= (1+cosAsinA+sinAcosA)(sinA−cosA)

= (sinA−cosA)(sinAcosA+sin2A+cos2A)sinAcosA

= sin3A−cos3AsinAcosA

= sin2AcosA−cos2AsinA

= 1cosA.sin2A1−1sinA.cos2A1

= secAcosec2A−cosecAsec2A

= R.H.S.

Step-by-step explanation:

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