sec³x ,Find the integrals of the given function with respect to x.
Answers
Answered by
21
HELLO DEAR,
GIVEN:-
∫sec³x dx = ∫secx.sec²x.dx
= secx.(tanx) - ∫secx tanx (tanx).dx
[integrating by parts]
= secxtanx - ∫sec³x.dx + ∫secx.dx
therefore,
2∫sec³x.dx = secxtanx + log|tan(π/4 + x/2)| + C.
=> ∫sec³x.dx = 1/2secxtanx + 1/2log|tan(π/4 + x/2)| + C'.
I HOPE ITS HELP YOU DEAR,. THANKS
GIVEN:-
∫sec³x dx = ∫secx.sec²x.dx
= secx.(tanx) - ∫secx tanx (tanx).dx
[integrating by parts]
= secxtanx - ∫sec³x.dx + ∫secx.dx
therefore,
2∫sec³x.dx = secxtanx + log|tan(π/4 + x/2)| + C.
=> ∫sec³x.dx = 1/2secxtanx + 1/2log|tan(π/4 + x/2)| + C'.
I HOPE ITS HELP YOU DEAR,. THANKS
Similar questions