Question

sec4 A - sec2 A = tan4 A + tan2 A​

Answer 1

hope it helps you......

Answer 2

Solution →

sec⁴A - sec²A = tan⁴A + tan²A

LHS →

= sec⁴A - sec²A

= sex²A ( sec²A - 1 )

We know that →

Sec²A - tan²A = 1

sec²A = 1 + tan²A

Sec²A - 1 = tan²A

By Putting these values ,

= ( 1 + tan²A) ( tan²A)

$\boxed{= tan^{4}A+tan^{2}A}$

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