Question

:) sec4 A – tanº A = 1 + 2 tan? A.​

Answer 1

Answer:

tan a will be equal to 1/2

Answer 2

Answer:

Step-by-step explanation:

Answer

Consider the L.H.S,

=sec  

4

A(1−sin  

4

A)−2tan  

2

A

=sec  

4

A−sec  

4

Asin  

4

A−2tan  

2

A

=sec  

4

A−  

cos  

4

A

sin  

4

A

​  

−2tan  

2

A

=sec  

4

A−tan  

4

A−2tan  

2

A

=[(sec  

2

A)  

2

−(tan  

2

A)  

2

]−2tan  

2

A

=[(sec  

2

A)−(tan  

2

A)][(sec  

2

A)+(tan  

2

A)]−2tan  

2

A

We know that

sec  

2

A−tan  

2

A=1

Therefore,

=sec  

2

A+tan  

2

A−2tan  

2

A

=sec  

2

A−tan  

2

A

=1

Hence, proved