Question

Sec⁴A(1-Sin⁴A)= 2 sec²A​

Answer 1

Answer:

Sec⁴A(1-Sin⁴A)= 2 sec²A

We are using formula of a² - b²

= 1+Sin²A - 2Sin²A / Cos² A

= 1 - Sin² A / Cos ² A

= Cos² A / Cos ² A

= 1

Hence LHS = RHS

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Some Formula of TRIGONOMETRY :-

1. cosec θ = 1/sin θ
2. sec θ = 1/cos θ
3. cot θ = 1/tan θ
4. sin θ = 1/cosec θ
5. cos θ = 1/sec θ
6. tan θ = 1/cot θ

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