Math, asked by Riomacrohonroldan, 9 months ago

Sec4x-tan4x=2sec2x=1

Answers

Answered by mysticd
1

Answer:

Secx-tanx=2sec²x-1

Step-by-step explanation:

LHS = sec⁴x-tanx

= (sec²x)² - (tan²x)²

= (sec²x+tan²x)(sec²x-tan²x)

= (sec²x+tan²x)×1

/* By Trigonometric identity:

sec²x-tan²x = 1 */

= sec²x+tan²x

= sec²x+(sec²x-1)

= 2sec²x-1

= RHS

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