Question

Sec6A-tan6 A = 1+3 sec²A -tan2A​

Answer 1

Answer:

Step-by-step explanation:

                   let m= sec^2 A  n=tan^2 A

               now it can be written as m^3 - n^3 =(m - n)(m^2+n^2 - mn)

                         the next solve it

                 let me know if u got this