Math, asked by khanmdshoaib123, 4 months ago

(SecA - 1)^2 - (tan A - Sin A)^2=(1-CosA)^2
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Answers

Answered by Anonymous

0

Answer:

Step-by-step explanation:

LHS=(SecA - 1)^2 - (tan A - Sin A)^2=(1-CosA)^2

=sec²A-2secA+1-tan²A-sin²A+2tanAsinA

=sec²A-tan²A+1--sin²A-2secA+tanAsinA

=1+cos²A-2/cosA+sin²A/cosA

=1+cos²A-2/cosA(1-sin²A)

=1+cos²A-2cos²A/cosA

=1+cos²A-2cosA

=(1-cosA)²=RHS

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