Question

secA - 1 / secA +1 = ( sinA/ 1+ cosA)²​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

sin²A+cos²A=1

Step-by-step explanation:

secA can be written as 1/cosA

((1/cosA)-1)/((1/cosA)+1)=(sinA/(1+cosA)²

(1-cosA/1+cosA)=sin²A/(1+cosA)²

after cancelling denominator in RHS

remaining terms are

1-cosA=sin²A/(1+cosA)

(1-cosA)*(1+cosA)=sin²A

(a-b)*(a+b)=a²-b²

1-cos²A=sin²A

therefore sin²A+cos²A=1