Math, asked by harsharathi560, 5 months ago

secA(1-sinA) = 1/secA+tanA

Answers

Answered by sandy1816

0

secA(1-sinA)

=secA-sinAsecA

=secA-tanA

=(secA-tanA)(secA+tanA)/secA+tanA

=sec²A-tan²A/secA+tanA

=1/secA+tanA

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