Math, asked by rahulrsmi143, 11 months ago

secA(1-sinA)(secA+tanA)=1​

Answers

Answered by Anonymous
1

secA(1-sinA)(secA+tanA)

=> 1/cosA(1-sinA)(secA+tanA) -----> we are simplifying secA

=> (1/cosA - sinA/cosA)(secA+tanA) ---> we are multiplying

=> (secA - tanA)(secA+tanA) --------> because 1/cosA = secA and sinA/cosA = tanA

=> sec^2A - tan^2A ---> using identity (a+b)(a-b) = a^2 - b^2

=> 1 (according to identity)

HOPE THIS HELPS U.

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